For what values of y is the expression \(\frac{6y-1}{y^2 - y-6}\)
MATHEMATICS
WAEC 2005
For what values of y is the expression \(\frac{6y-1}{y^2 - y-6}\)
- A. \(\frac{1}{6}, \frac{1}{4}\)
- B. 3, -2
- C. -3, 2
- D. 0,1
Correct Answer: B. 3, -2
Explanation
The expression is not defines when y2 - y - 6 = 0
=> y2 - 3y + 2y - 6 = 0 => (y-3)(y+2) = 0 => y
-3 = 0 or y + 2 = 0 => y = 3 or -2
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