Find the equation whose roots are \(-\frac{2}{3}\) and 3
MATHEMATICS
WAEC 2003
Find the equation whose roots are \(-\frac{2}{3}\) and 3
- A. 3x2+11x-6=0
- B. 3x2+7x+6=0
- C. 3x2-11x-6=0
- D. 3x2-7x-6=0
Correct Answer: D. 3x2-7x-6=0
Explanation
\(x = -\frac{2}{3} \implies x + \frac{2}{3} = 0\)
\(x = 3 \implies x - 3 = 0\)
\(\implies (x - 3)(x + \frac{2}{3}) = 0\)
\(x^2 - 3x + \frac{2}{3}x - 2 = 0\)
\(x^2 - \frac{7}{3}x - 2 = 0\)
\(3x^2 - 7x - 6 = 0\)
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