If \(\frac{3^{(1-n)}}{9^{-2n}}=\frac{1}{9}\) find n
MATHEMATICS
WAEC 2003
If \(\frac{3^{(1-n)}}{9^{-2n}}=\frac{1}{9}\) find n
- A. \(-\frac{3}{2}\)
- B. \(\frac{1}{3}\)
- C. -1
- D. -3
Correct Answer: C. -1
Explanation
\(\frac{3^{(1-n)}}{9^{-2n}}=\frac{1}{9}\\
3^{1-n}\times 3^{-2(-2n)} = 3^{-2}\\
1-n-2(-2n)= -2\\
1-n+4n=-2\\
n=-1\)
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