In the diagram O is the center of the circle, ∠SOR = 64° and ∠PSO...
MATHEMATICS
WAEC 2002
In the diagram O is the center of the circle, ∠SOR = 64° and ∠PSO = 36°. Calculate ∠PQR
- A. 100°
- B. 96°
- C. 94°
- D. 86°
Correct Answer: D. 86°
Explanation
< OSR = < ORS = \(\frac{180° - 64°}{2}\) = 58°
< PSR = 36° + 58° = 94°
< PSR + < PQR = 180°
94° + < PQR = 180° \(\implies\) < PQR = 180° - 94° = 86°
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