Factorize \(6x^2 + 7x - 20\)
MATHEMATICS
WAEC 2001
Factorize \(6x^2 + 7x - 20\)
- A. (6x - 5)(x + 4)
- B. 2(3x-5)(x+2)
- C. (3x+4)(2x-5)
- D. (3x-4)(2x+5)
Correct Answer: D. (3x-4)(2x+5)
Explanation
\(6x^2 + 7x - 20\)
= \(6x^2 + 15x - 8x - 20\)
= \(3x(2x + 5) - 4(2x + 5)\)
= \((3x - 4)(2x + 5)\)
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