Find the value of x such that the expression \(\frac{1}{x}+\frac{4}{3x}-\frac{5}{6x}+1\) equals zero...
MATHEMATICS
WAEC 2000
Find the value of x such that the expression \(\frac{1}{x}+\frac{4}{3x}-\frac{5}{6x}+1\) equals zero
- A. \(\frac{1}{6}\)
- B. \(\frac{1}{4}\)
- C. \(\frac{-3}{2}\)
- D. \(\frac{-7}{6}\)
Correct Answer: C. \(\frac{-3}{2}\)
Explanation
\(\frac{1}{x} + \frac{4}{3x} - \frac{5}{6x} + 1 = 0\)
\(\frac{6 + 8 - 5 + 6x}{6x} = 0\)
\(\frac{9 + 6x}{6x} = 0 \implies 9 + 6x = 0\)
\(6x = -9 \implies x = \frac{-3}{2}\)
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