In the diagram, DE||BC, |AD| = x cm and |DB| = |AE| = ycm. Find
MATHEMATICS
WAEC 1999
In the diagram, DE||BC, |AD| = x cm and |DB| = |AE| = ycm. Find |CE| in terms of x and y
- A. x
- B. \(\frac{x^2}{y}\)
- C. \(\frac{y}{x^2}\)
- D. \(\frac{y^2}{x}\)
Correct Answer: D. \(\frac{y^2}{x}\)
Explanation
\(\frac{x}{x+y}=\frac{y}{x+CE}\\
xy + xCE = xy + y^2\\
?xCE = y^2\\
CE=\frac{y^2}{x}\)
Post an Explanation Or Report an Error
If you see any wrong question or answer, please leave a comment below and we'll take a look. If you doubt why the selected answer is correct or need additional more details? Please drop a comment or Contact us directly. Your email address will not be published. Required fields are marked *