Make q the subject of the relation t = √(pq/r - r\(^2\)q)
MATHEMATICS
WAEC 1997
Make q the subject of the relation t = √(pq/r - r\(^2\)q)
- A. q = \(\frac{rt^2}{(p - r^3)}\)
- B. q = \(\frac{t^2}{(p - r^2)}\)
- C. q = \(\frac{rt}{(p - r^3)}\)
- D. q = \(\frac{(p - r^3)}{rt^2}\)
Correct Answer: A. q = \(\frac{rt^2}{(p - r^3)}\)
Explanation
t = √pq/r - r\(^2\)q
multiply both sides by the L.C.M, r
r\(^2\) = pq - qr\(^3\)
collect like terms on the RHS
q(p - r3) = rt\(^2\)
q = \(\frac{rt^2}{(p - r^3)}\)
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