The force of repulsion between two point positive charges 5\(\mu\)C and 8\(\mu\)C separated at a...
PHYSICS
JAMB 1998
The force of repulsion between two point positive charges 5\(\mu\)C and 8\(\mu\)C separated at a distance of 0.02 map art is. [\(\frac{1}{4{\pi}{\varepsilon}_o}\) = 9 x 109Nm2C-2]
- A. 1.8 x 10-10N
- B. 9.0 x 10-8N
- C. 9.0 x 102N
- D. 4.5 x 103N
Correct Answer: C. 9.0 x 102N
Explanation
F =\(\frac{1}{4{\pi}{\varepsilon}_o}\) x \(\frac {q_1q_2}{r^2}\)
F =\(\frac {5 {\times} 10 {\times} 8 {\times} 10}{0.002 {\times} 0.002}\) x 9 x 10
F = 900N
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