The force of attraction between two point masses is 10 -4 N when the distance
PHYSICS
JAMB 1998
The force of attraction between two point masses is 10-4N when the distance between them is 0.18m. If the distance is reduced to 0.06m, calculate the force.
- A. 1.1 x 10-5N
- B. 3.3 x 10-5N
- C. 3.0 x 10-4N
- D. 9.0 x 10-4N
Correct Answer: D. 9.0 x 10-4N
Explanation
F \(\alpha \frac{1}{r^2}\)
therefore, \(\frac{F_1}{F_2}\) = \(\frac{r_1}{(r_2)^2}\)
\(\frac{10^{-4}}{F_2}\) = \(\frac{(0.06)^2}{(0.18)^2}\)
F = 9 x 10-4N
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