An electric current of 2 amperes flows in a heating coil of resistance 50 ohms
PHYSICS
JAMB 1995
An electric current of 2 amperes flows in a heating coil of resistance 50 ohms for 3 minutes 20 seconds. Determine the heat produced
- A. 0.5kJ
- B. 8.0kJ
- C. 20.0kJ
- D. 40.0kJ
Correct Answer: D. 40.0kJ
Explanation
Heat energy = Elect. energy
heat energy= I2RT
= 2 X 2 X 50 X 200
= 40000J
to convert to kJ, divide J by 1000
hence, \(\frac{40000}{1000}\) = 40kJ
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