The energy contained in a wire when it extended by 0.02m by a force 500
PHYSICS
JAMB 1995
The energy contained in a wire when it extended by 0.02m by a force 500 N is
- A. 5J
- B. 10J
- C. 103J
- D. 104J
Correct Answer: A. 5J
Explanation
Energy = \(\frac{1}{2}\)Fe
= \(\frac{1}{2}\) x 500 x 0.02
E = 5J
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