A certain radioisotope of \(^{235}_{92}U\) emits four alpha particles and three beta particles. The mass...
PHYSICS
JAMB 1994
A certain radioisotope of \(^{235}_{92}U\) emits four alpha particles and three beta particles. The mass number and the atomic number of the resulting elements respectively are
- A. 219 and 87
- B. 84 and 223
- C. 223 and 87
- D. 219 and 81
Correct Answer: A. 219 and 87
Explanation
\(^{235}_{92}U\) \(\to\) 4\((^{4}_{2}\alpha)\) + 3\((^{0}_{-1}e)\) + \(^{b}_{a}y\)
a + (4 + 2) + (3x - 1) = 92 \(\Rightarrow\) a = 87
b + (4 x 4) + (3 x 0) = 235 \(\Rightarrow\) b = 219
\(^{b}_{a}Y\) = \(^{219}_{87}Y\)
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