An object is placed directly below a glass block of thickness 3.0cm. Calculate the lateral...
PHYSICS
JAMB 1994
An object is placed directly below a glass block of thickness 3.0cm. Calculate the lateral displacement of the object if the refractive index of the glass is 1.5.
- A. 1.0cm
- B. 1.5cm
- C. 2.0cm
- D. 2.5cm
Correct Answer: A. 1.0cm
Explanation
1.5 = \(\frac{3}{\text {apparent displacement}}\)
Apparent depth = 2cm
displacement = 3 - 2
= 1cm
Post an Explanation Or Report an Error
If you see any wrong question or answer, please leave a comment below and we'll take a look. If you doubt why the selected answer is correct or need additional more details? Please drop a comment or Contact us directly. Your email address will not be published. Required fields are marked *