4g of a radioactive material of half-life 10 days is spilled on a laboratory floor.

PHYSICS
JAMB 1991

4g of a radioactive material of half-life 10 days is spilled on a laboratory floor. How long would it take to disintegrate 3.5g of the material?

  • A. 1\(\frac{1}{4}\) days
  • B. 8\(\frac{1}{4}\) days
  • C. 30 days
  • D. 80 days

Correct Answer: C. 30 days

Explanation

half-life = 10 days

after 10 days, the 4g of element = 2g remaining with 2g disintegrated

after 10 days, 2g of element = 1g left with 1g disintegrated

hence, after 20 days, 3g of the element has been disintegrated with 1g left.

after 10 days, the 1g of element = 0.5g left with 0.5g disintegrated

after 30 days, we have 0.5g of element left with 3.5g disintegrated.



Post an Explanation Or Report an Error
If you see any wrong question or answer, please leave a comment below and we'll take a look. If you doubt why the selected answer is correct or need additional more details? Please drop a comment or Contact us directly. Your email address will not be published. Required fields are marked *
Add Math
Don't want to keep filling in name and email whenever you make a contribution? Register or login to make contributing easier.