The table below shows the total revenue schedule of a farmer who produces maizze. Use...

ECONOMICS
WAEC 2018

The table below shows the total revenue schedule of a farmer who produces maizze. Use the informatiom in the table to answer the qeston that follows;

Output (in bags)Total Revenue ($)
00
16
212
318
424
530
636

(a) At each level of output, calculate the farmer's marginal revenue (MR).

(b) What is the price of a bag of maize? Explain your answer.

(c) In what market structure is the farmer operating? Give a reason for your answer.

Explanation

(a) MR = \(\frac{\bigtriangleup TR} {\bigtriangleup Q}\)

MR\(_{1}\) = \(\frac{6 – 0}{1 - 0}\) = \(\frac{6}{1}\) = 6

MR\(_{2}\) = \(\frac{12 - 6}{2 - 1}\) = \(\frac{6}{1}\) = 6

MR\(_{3}\) = \(\frac{18 - 12}{3 - 2}\) = \(\frac{6}{1}\) = 6

MR\(_{4}\) = \(\frac{24 - 18}{4 - 3}\) = \(\frac{6}{1}\) = 6

MR\(_{5}\) = \(\frac{30 - 24}{5 - 4}\) = \(\frac{6}{1}\) = 6

MR\(_{6}\) = \(\frac{36 -30}{6 - 5}\) = \(\frac{6}{1}\) = 6

(b) P = AR = \(\frac{TR}{Q}\) e.g AR\(_{1}\) = \(\frac{6}{1}\) = $6.00

Therefore the price of a bag of maize is $6.00.

(c) The farmer operates in a perfectly competitive market. In perfect competition MR = AR. Since from the calculation, MR = $6.00 and AR =$6.00, then the farmer operates in perfect competitionORbecause price is fixed at $6.00 at all levels of output.



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