A homozygous tall, red flower plant was crossed with a homozygous dwarf, white flower plant....

BIOLOGY
WAEC 2019

A homozygous tall, red flower plant was crossed with a homozygous dwarf, white flower plant. The F1 were selfed and 160 F2 plants were obtained.

a.(i) Name the type of genetic cross. [1 marks]

(ii) Stateonereason for the answer in 4(a)(i). [1 marks]

b.(i) What is evolution? [2 marks]

(ii) With the aid of a genetic diagram, state the phenotypic ratio of F2 generation. [13 marks]

(iii) Calculate the number of tall and white flowers that would be obtained in theF2generation. [3 marks]

Explanation

a. (i) Type of genetic cross: Dihybrid

(ii) Reason for answer: Two characters are involved in the cross/involves two characters separable in inheritance.

b. (i) Phenotype of F1: Tall and Red.

(ii) Genetic Diagram

Let T represent the gene for Tallness;

t represent the gene for Dwarfism;

R represent the gene for Red;

r represent the gene for White.

OR

Parental genotype TtRr X TtRr

XTRTrtRtr
TR

TTRR

Tall

Red

TTRr

Tall

Red

TtRR

Tall

Red

TtRr

Tall

Red

TrTTRr Tall RedTTrr Tall WhiteTtRr Tall Red

Ttrr

Tall

White

tRTtRR Tall RedTtRr Tall Red

ttRR

Dwarf

Red

ttRr

Dwarf

Red

trTtRr Tall RedTtrr Tall WhitettRR Dwarf Red

ttrr

Dwarf

White

Crosses of parental genotypes

Tall and Red - 9

Tall and White - 3

Dwarf and Red - 3

Dwarf and White - 1

Parental genotype

Parental gametes (TR, Tr, tR, tr) shown

Correct Crosses of parental gamete

Phenotypic ratio 9:3:3:1

(iii) Calculation of Tall and White flowers in F2

(3/16) x (160/1) = 30



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