A cell whose internal resistance is 0.55\(\Omega\) delivers a current of 4 A to an
PHYSICS
JAMB 2022
A cell whose internal resistance is 0.55\(\Omega\) delivers a current of 4 A to an external resistor. The lost voltage of the cell is?
- A. 4.00 V
- B. 2.20 V
- C. 0.15 V
- D. 8.00 V
Correct Answer: B. 2.20 V
Explanation
Lost voltage = I x R
= 4 x 0.55
= 2.2V
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