Without using tables, find the value of \(\frac{\sin 20°}{\cos 70°} + \frac{\cos 25°}{\sin 65°}\)...
MATHEMATICS
WAEC 1995
Without using tables, find the value of \(\frac{\sin 20°}{\cos 70°} + \frac{\cos 25°}{\sin 65°}\)
- A. 2
- B. 1
- C. 0
- D. -1
Correct Answer: A. 2
Explanation
Note: sin 20° = cos 70° hence
\(\frac{\sin 20}{\cos 70} = 1\)
Also, cos 65° = sin 25°
\(\frac{\cos 65}{\sin 25} = 1\)
\(\therefore \frac{\sin 20}{\cos 70} + \frac{\cos 65}{\sin 25}\)
= 1 + 1
= 2
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