In the diagram below, AB//CD, the bisector of ?BAC and ?ACD meet at E. Find...

MATHEMATICS

WAEC 1995

In the diagram below, AB//CD, the bisector of ?BAC and ?ACD meet at E. Find the value of ?AEC

A. 30°
B. 45°
C. 60°
D. 90°

Correct Answer: D. 90°

Explanation

Ae is a bisector of BAC => EAC = 45^o

CE is the bisector of ACD => ACE = 45^o

AEC = 180^o - [EAC + ACE]

= 180^o - (45^o + 45^o) = 180^o - 90^o = 90^o

Previous Next

Back to WAEC 1995 Questions

Post an Explanation Or Report an Error

If you see any wrong question or answer, please leave a comment below and we'll take a look. If you doubt why the selected answer is correct or need additional more details? Please drop a comment or Contact us directly. Your email address will not be published. Required fields are marked *