In the diagram below, PQ is parallel to TU, ?PQR = 50°, ?QRS = 86°
MATHEMATICS
WAEC 1995
In the diagram below, PQ is parallel to TU, ?PQR = 50°, ?QRS = 86° and ?STU = 64°. Calculate the value of x.
- A. 136°
- B. 120°
- C. 108°
- D. 100°
Correct Answer: D. 100°
Explanation
y = 86° - 50° [Alternate ∠s are equal]
y = 86° - 50° = 36°
a = y = 36° [Alternate ∠s]; b = 64° [Alternate ∠s;]
x = a + b = (36° + 64°)
=100°
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