Evaluate \(\log_{10} 25 + \log_{10} 32 - \log_{10} 8\)
MATHEMATICS
WAEC 1992
Evaluate \(\log_{10} 25 + \log_{10} 32 - \log_{10} 8\)
- A. 0.2
- B. 2
- C. 100
- D. 409
Correct Answer: B. 2
Explanation
\(\log_{10} 25 + \log_{10} 32 - \log_{10} 8\)
= \(\log_{10} (\frac{25 \times 32}{8})\)
= \(\log_{10} 100 \)
= 2
Post an Explanation Or Report an Error
If you see any wrong question or answer, please leave a comment below and we'll take a look. If you doubt why the selected answer is correct or need additional more details? Please drop a comment or Contact us directly. Your email address will not be published. Required fields are marked *