If events X and Y are mutually exclusive, P(X) = 1/3 and P(Y) = 2/5,
MATHEMATICS
WAEC 1991
If events X and Y are mutually exclusive, P(X) = 1/3 and P(Y) = 2/5, P(X∪Y) is
- A. 0
- B. 2/15
- C. 4/14
- D. 11/15
Correct Answer: D. 11/15
Explanation
P(X \(\cup\) Y) = \(\frac{1}{3} + \frac{2}{5}\)
= \(\frac{11}{15}\)
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