Consider the following equation; Cr 2 O 7 (aq) 2- + 14H + (aq) +
CHEMISTRY
WAEC 2002
Consider the following equation; Cr2O7(aq)2- + 14H+(aq) + 6e- → 2Cr3+(aq) + 7H2O(I). The oxidation number of chromium changes from
- A. -2 to + 3
- B. - 2 to + 6
- C. + 6 to + 3
- D. + 7 to + 6
Correct Answer: C. + 6 to + 3
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