Find the value of x if \(\frac{\sqrt{2}}{x + \sqrt{2}}\) = \(\frac{1}{x - \sqrt{2}}\)
MATHEMATICS
JAMB 2020
Find the value of x if \(\frac{\sqrt{2}}{x + \sqrt{2}}\) = \(\frac{1}{x - \sqrt{2}}\)
- A. 3\(\sqrt{2}\) + 4
- B. 3\(\sqrt{2}\) - 4
- C. 3 - 2\(\sqrt{2}\)
- D. 4 + 2\(\sqrt{2}\)
Correct Answer: A. 3\(\sqrt{2}\) + 4
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