Mathematics Past Questions And Answers
Simplify \(\frac{4\frac{3}{4} - 6\frac{1}{4}}{4\frac{1}{5} \text{ of } 1\frac{1}{4}}\)
- A. -7\(\frac{7}{8}\)
- B. \(\frac{-2}{7}\)
- C. \(\frac{-10}{21}\)
- D. \(\frac{10}{21}\)
Simplify; [(\(\frac{16}{9}\))\(^{\frac{-3}{2}}\) x 16\(^{\frac{-3}{2}}\)]\(^{\frac{1}{3}}\)
- A. \(\frac{3}{4}\)
- B. \(\frac{9}{16}\)
- C. \(\frac{3}{8}\)
- D. \(\frac{1}{4}\)
Find the equation of the locus of a point A(x, y) which is equidistant from B(0, 2) and C(2, 1)
- A. 4x + 2y = 3
- B. 4x - 3y = 1
- C. 4x - 2y = 1
- D. 4x + 2y = -1
(a) Copy and complete the table of values for the relation y=2x\(^2\) - x - 2 for 4 ≤ x ≤ 4.
| x | -4 | -3 | -2 | -2 | 0 | 1 | 2 | 3 | 4 |
| y | 19 | -2 | 26 |
(b) Using a scale of 2 cm to 1 unit on the x-axis and 2 cm to 5 units on the y-axis, draw the graph of y = 2x\(^2\) - x - 2 for 4 ≤ x ≤ 4.
(c) On the same axes, draw the graph of y = 2x + 3.
(d) Use the graph to find the: (i) roots of the equation 2x-3r-5 0; (i) range of values of x for which 2x\(^2\) -x - 2<0.
View Discussion (0)WAEC 2021 THEORYEvaluate \(\int \sin 3x \mathrm d x\)
- A. (2/3) cos 3x + c
- B. (1/3) cos 3x + c
- C. (-1/3) cos 3x + c
- D. (-2/3) cos 3x + c
Mrs Gabriel is pregnant. The probability that she will give birth to a girl is 1/2 and with blue eyes is 1/4. What is the probability that she will give birth to a girl with blue eyes?
- A. 1
- B. \(\frac{3}{4}\)
- C. \(\frac{1}{8}\)
- D. \(\frac{1}{4}\)
(a) Given that \(\sin x = 0.6, 0° \leq x \leq 90°\), evaluate \(2\cos x + 3\sin x\), leaving your answer in the form \(\frac{m}{n}\), where m and n are integers.
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In the diagram, a semi-circle WXYZ with centre O is inscribed in an isosceles triangle ABC. If /AC/ = /BC/, |OC| = 30 cm and < ACB = 130°, calculate, correct to one decimal place, the (i) radius of the circle ; (ii) area oc the shaded portion. [Take \(\pi = \frac{22}{7}\)].
View Discussion (0)WAEC 2011 THEORYSolve for x and y in the equations below x2 - y2 = 4 x + y = 2
- A. x = 0, y = -2
- B. x = 0, y = 2
- C. x = 2, y = 0
- D. x = -2, y = 0
If a = 2, b = -2 and c = -\(\frac{1}{2}\), evaluate (ab2 - bc2)(a2c - abc)
- A. 2
- B. -28
- C. -30
- D. -34
P(3,4) and Q(-3, -4) are two points in a plane. Find the gradient of the line that is normal to the line PQ.
- A. \(\frac{4}{3}\)
- B. \(\frac{3}{4}\)
- C. \(\frac{-3}{4}\)
- D. \(\frac{-4}{3}\)


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