Mathematics Past Questions And Answers
In the diagram, PQ is a diameter of the circle and ∠PRS = 58°. Find ∠STQ.
- A. 29°
- B. 32°
- C. 42°
- D. 53°
The locus of a point P which is equidistant from two given points S and T is
- A. the perpendicular bisector of ST
- B. the angle bisector of PS and ST
- C. a perpendicular to ST
- D. a line parallel to ST
The dimensions of water tank are 13cm, 10cm and 70cm. If it is half-filled with water, calculate the volume of water in litres
- A. 4.55 litres
- B. 7.50 litres
- C. 8.10 litres
- D. 9.55 litres
If p varies inversely as the cube of q and q varies directly as the square of r, what is the relationship between p and r?
- A. p varies directly as r3
- B. p varies inversely as r6
- C. p varies inversely as6√P
- D. p varies directly as r6
(a) If \(f(x) = \frac{4 - 5x}{2}\), and \(g(x) = x + 6, x \in R\), find \(f \circ g^{-1}\).
(b) P(x, y) divides the line joining (7, -5) and (-2, 7) internally in 5 : 4. Find the coordinates of P.
View Discussion (0)WAEC 2017 THEORY(a) Write down the first four terms of the binomial expansion of \((2 - \frac{1}{2})^{5}\) in ascending powers of x.
(b) Use your expansion in (a) above to find, correct to two decimal places, the value of \((1.99)^{5}\).
View Discussion (0)WAEC 2007 THEORYGiven that M : (x, y) \(\to\) (7x, 3x - y) and N : (x, y) \(\to\) (2x - y; 5x + 3y)
(a) write down matrices M and N of the linear transformation
(b) find the image of P(2, -3) under the linear transformation N followed by M;
(c) find the coordinates of the point Q whose image is Q(2, 4) under the linear transformation N
View Discussion (0)WAEC 2019 THEORYMake F the subject of the formula t = \(\sqrt{\frac{v}{\frac{1}{f} + \frac{1}{g}}}\)
- A. \(\frac{gv-t^2}{gt^2}\)
- B. \(\frac{gt^2}{gv-t^2}\)
- C. \(\frac{v}{\frac{1}{t^2} - \frac{1}{g}}\)
- D. \(\frac{gv}{t^2 - g}\)
From the top of a cliff 20m high, a boat can be sighted at sea 75m from the foot of the cliff. Calculate the angle of depression of the boat from the top of the cliff
- A. 14.9o
- B. 15.5o
- C. 74.5o
- D. 75.1o
Simplify \(3\sqrt{12} + 10\sqrt{3} - \frac{6}{\sqrt{3}}\)
- A. \(7\sqrt{3}\)
- B. \(10\sqrt{3}\)
- C. \(14\sqrt{3}\)
- D. \(18\sqrt{3}\)