Mathematics Past Questions And Answers
Each of the base angles of a isosceles triangle is 58° and the verticles of the triangle lie on a circle. Determine the angle which the base of the triangle subtends at the centre of the circle.
- A. 128°
- B. 16°
- C. 64°
- D. 58°
Using a scale of 2cm to 1 unit on the x- axis and 1cm to 1 unit on the y- axis, draw on the same axes the graphs of \(y = 3 + 2x - x^{2}; y = 2x - 3\) for \(-3 \leq x \leq 4\). Using your graph:
(i) solve the equation \(6 - x^{2} = 0\);
(ii) find the maximum value of \(3 + 2x - x^{2}\);
(iii) find the range of x for which \(3 + 2x - x^{2} \leq 1\), expressing all your answers correct to one decimal place.
View Discussion (0)WAEC 1991 THEORY
A particle starts from rest and moves through a distance \(S = 12t^{2} - 2t^{3}\) metres in time t seconds. Find its acceleration in 1 second.
- A. 24\(ms^{-2}\)
- B. 18\(ms^{-2}\)
- C. 12\(ms^{-2}\)
- D. 10\(ms^{-2}\)
Evaluate \(\int_0^1 4x - 6\sqrt[3] {x^2}dx\)
- A. - \(\frac{5}{8}\)
- B. - \(\frac{8}{5}\)
- C. \(\frac{8}{5}\)
- D. \(\frac{5}{8}\)
Find the value of x in the equation 3x\(^2\) - 8x - 3 = 0
- A. \(\frac{1}{3},-3\)
- B. \(-\frac{1}{3},-3\)
- C. \(-\frac{1}{3},3\)
- D. \(\frac{1}{3},3\)
| Scores | 1 | 2 | 3 | 4 | 5 | 6 |
| Frequency | 2 | 5 | 13 | 11 | 9 | 10 |
The table shows the distribution of outcomes when a die is thrown 50 times. Calculate the :
(a) Mean deviation of the distribution ; (b) probability that a score selected at random is at least a 4.
View Discussion (0)WAEC 2014 THEORYFactorize: \(16x^4 - y^4\)
- A. \((2x - y)(2x + y)(4x^2 + y^2)\)
- B. \((2x + y)(2x + y)(4x^2 + y^2)\)
- C. \((2x - y)(2x - y)(4x^2 + y^2)\)
- D. \((2x - y)(2x + y)(4x^2 - y^2)\)
Which of these inequalities is represented by the shaded portion of the graph?
- A. 2y + x - 3< 0
- B. 2y - x - 3< 0
- C. 2y - x + 3< 0
- D. 2y + x +3< 0
In the diagram, ∠POQ = 150 and the radius of the circle PSQR is 4.2cm. [take π = 22/7]
What is the length of the minor arc?
- A. 11cm
- B. 15.4cm
- C. 17.64cm
- D. 23.10cm
Multiply (x2 - 3x + 1) by (x - a)
- A. x3 - (3 + a) x2 + (1 + 3a)x - a
- B. x3 - (3 - a)x2 + 3ax - a
- C. x3 - (3 - a)x2 - (1 = 3a) - a
- D. x3 + (3 - a)x2 + (1 + 3a) - a