Correct Answer: B. gibberellin

Correct Answer: D) 4

Correct Answer: D. smoke

Explanation

Solid in gas mixture: Smoke, ice clouds, dust.

Liquid in gas mixture: fog, mist, vapour and hair sprays.

Gas in solid mixture: aerogel, Styrofoam.

Correct Answer: C. HCHO

Correct Answer: B) Iron, iron

Explanation

Reduction is a process in which a reactant gains electrons, which means that the electrode where reduction is taking place is where electrons are being gained. In this case, reduction is taking place at the Iron half-cell because Iron is gaining electrons and becoming positively charged. Therefore, the correct answer is option B: Iron, Iron.

Additionally, the question asks which electrode is positively charged. A positively charged electrode is an electrode that has lost electrons. In this case, Zinc is losing electrons and becoming negatively charged, so the Zinc half-cell is negatively charged.

It's important to note that the salt bridge is used to maintain electrical neutrality between the two half-cells, and the copper wire is used to allow the flow of electrons between the two half-cells.

To summarize, in this question, reduction is taking place at the Iron half-cell, which is also positively charged. The Zinc half-cell is negatively charged because Zinc is losing electrons. The salt bridge maintains electrical neutrality between the two half-cells, and the copper wire allows the flow of electrons.

Correct Answer: A) 100KJ

Correct Answer: C. Nylon and creatine, polyethylene and haemoglobin

Correct Answer: C) hydrolysis

Correct Answer: D. Activation energy

Explanation

(a)(i) Diffusion is the movement of particles from the region of higher concentration to the region of lower concentration

(ii) Charles' Law states that the volume of a given mass of gas is directly proportional to its absolute temperature at a constant pressure.

(iii)

(iv) \(\frac{V_1}{T_1} = \frac{V_2}{T_2}\) \(T_2 = \frac{T_1V_2}{V_1}\)

\(T_2 = \frac{300 \times 300}{150} = 600k\)

(v)(i) Solid < liquid < gas / solid, liquid, gas

(ii) Gas < liquid < Solid / gas, liquid, solid

b)(i) In a reversible reaction at equilibrium, if any will of the factors affecting the equilibrium is altered, the position of equilibrium will change so as to annul the effect of the change

(ii) Oxide I

% of O\(_2\) = 11.1 %

% by mass of metal = 88.9%

11.1 of O\(_2\) combined with 88.9 of metal

100 of O\(_2\) = \(\frac{100}{88.9}\) = 800.9g

Oxide II

% of O\(_2\) = 20%

% by mass of metal = 80%

20 of O\(_2\) combined with 80 of metal

100 of O\(_2\) = \(\frac{100}{ 80}\) = 400g

Ratio of metal in both oxides = 800. 9 : 400

2 : 1

(c)(i) Add water to mixture A, B and C and stir.

— C dissolves

— Filter to obtain C as filtrate and A and B as residue

— Heat residue until melted.

— Separate by simple distillation

— Evaporate filtrate to dryness to obtain solid C

— Pure A is collected at 117°C and pure B at 160°C

(ii) Mass of mixture = 25.25g

Mass A + B = 7.52g + 8.48g

= 16.00g

Mass of C = 25.25 - 16.00g

= 9.25g

% of C in mixture = \(\frac{9.25}{25.25}\) x 100

= 36.6%