Correct Answer: B. symbol

Correct Answer: D) triplonema

Explanation

During meiosis, which is a type of cell division that produces gametes (sperm or egg cells), there are two stages of division: meiosis I and meiosis II. The prophase stage is the first stage of meiosis I. During this stage, the chromatin (long, thin strands of DNA and protein) in the nucleus condenses into visible chromosomes. Each chromosome has already replicated, so it consists of two identical sister chromatids. The nuclear envelope also breaks down, and the spindle fibers begin to form. The options given in this question are all terms used to describe different sub-stages of the prophase stage of meiosis. Leptonema is the first sub-stage of prophase I, where the chromosomes become visible and begin to condense. Zygonema is the second sub-stage, where the homologous chromosomes begin to pair up with each other. Pachynema is the third sub-stage, where the homologous chromosomes become tightly bound to each other through a process called synapsis. The correct answer to this question is option D, triplonema, which is not a sub-stage of prophase I. Instead, it is a sub-stage of the next stage of meiosis I, called metaphase I. During this stage, the homologous chromosomes align along the equator of the cell and attach to the spindle fibers. Triplonema is a sub-stage of metaphase I where the homologous chromosomes begin to separate from each other, but are still connected at the site of crossing over. To summarize, the prophase stage of meiosis I is characterized by the condensation of chromosomes, breakdown of the nuclear envelope, and formation of spindle fibers. Leptonema, zygonema, and pachynema are all sub-stages of prophase I, while triplonema is a sub-stage of metaphase I. The correct answer to this question is option D.

Explanation

(a) MR = \(\frac{\bigtriangleup TR} {\bigtriangleup Q}\)

MR\(_{1}\) = \(\frac{6 – 0}{1 - 0}\) = \(\frac{6}{1}\) = 6

MR\(_{2}\) = \(\frac{12 - 6}{2 - 1}\) = \(\frac{6}{1}\) = 6

MR\(_{3}\) = \(\frac{18 - 12}{3 - 2}\) = \(\frac{6}{1}\) = 6

MR\(_{4}\) = \(\frac{24 - 18}{4 - 3}\) = \(\frac{6}{1}\) = 6

MR\(_{5}\) = \(\frac{30 - 24}{5 - 4}\) = \(\frac{6}{1}\) = 6

MR\(_{6}\) = \(\frac{36 -30}{6 - 5}\) = \(\frac{6}{1}\) = 6

(b) P = AR = \(\frac{TR}{Q}\) e.g AR\(_{1}\) = \(\frac{6}{1}\) = $6.00

Therefore the price of a bag of maize is $6.00.

(c) The farmer operates in a perfectly competitive market. In perfect competition MR = AR. Since from the calculation, MR = $6.00 and AR =$6.00, then the farmer operates in perfect competitionORbecause price is fixed at $6.00 at all levels of output.

Correct Answer: A. parallelism

Correct Answer: D. temperature of the Liquid rises

Correct Answer: A. injustice

Correct Answer: A. Pass

Explanation

(a)

(b)

(c)(i) 2x\(^{2}\) + x = 10 \(\equiv\) 2x\(^{2}\) + x - 10 = 0

Thus, the solution of 2x\(^{2}\) + x - 10 = 0 are the values of x at which the curve cuts the x- axis.

x = -2.5 or x = 2.

(ii) 2x\(^{2}\) + x - 10 = 2x

To solve the given equation, we first draw the graph of y = 2x: when x = -2, y = 2(-2) = -4; when x = 3, y = 2(3) = 6.

The values of x at which y = 2x\(^{2}\) + x - 10 and y = 2x intersect give the solution of 2x\(^{2}\) + x - 10 = 2x.

These are x = -2 or x = 2.5.

Correct Answer: C. DROP function

Correct Answer: C. N250,000