Explanation

(a) Total for A = 1,800,000 i.e adding the years together

Total for B = 2,300,000

Total for C = 2,900,000

Total for D = 2,200,000

Grand Total = 9,200,000

State Quantity

1998 production A = 600,000

B = 700,000

C = 800,000

D =400,000

2,500,000

State A 600,000 = 600,000 x 360° =6 x 360 = 432 = 86.4°

2,500,000 25 5

State B 700,000 =700,000 x 360°=2.520 =504 = 100.8°

2,500,000 25 5

State C 800,000 =800,000 x 360° =8 x 360 =2,880= 576 = 115.2

2,500,000 25 25 5

State D 400,000 =400,000 x 360° =1440 = 57.6°

2,500,000 25 5

(a) Total for A = 1,800,000 i.e adding the years together

Total for B = 2,300,000

Total for C = 2,900,000

Total for D = 2,200,000

Grand Total = 9,200,000

State Quantity

1998 production A = 600,000

B = 700,000

C = 800,000

D =400,000

2,500,000

State A 600,000 = 600,000 x 360° =6 x 360 = 432 = 86.4°

2,500,000 25 5

State B 700,000 =700,000 x 360°=2.520 =504 = 100.8°

&nbs

Explanation

\(2x^{2} - 7x + 4 = 0\)

\(\alpha + \beta = \frac{7}{2}\)

\(\alpha \beta = \frac{4}{2} = 2\)

\(\frac{\alpha}{\beta} + \frac{\beta}{\alpha} = \frac{\alpha^{2} + \beta^{2}}{\alpha \beta}\)

= \(\frac{(\alpha + \beta)^{2} - 2\alpha \beta}{\alpha \beta}\)

= \(\frac{(\frac{7}{2})^{2} - 2(2)}{2}\)

= \(\frac{(\frac{49}{4} - \frac{16}{4})}{2}\)

= \(\frac{33}{8}\)

\(\frac{\alpha}{\beta} \times \frac{\beta}{\alpha} = 1\)

\(\therefore Equation : x^{2} - \frac{33}{8}x + 1 = 0\)

Correct Answer: B. 22.00

Correct Answer: B. dispense

Explanation

A judge is required to dispense justice fairly.

dispense; pass, give out

Explanation

(a) A body is said to be moving with uniform acceleration when its time rate of increase of velocity is constant. It is measured in m/s\(^2\). It is a vector quantity.

The above sketch shows the v-t graph of the ball. The velocity decreases uniformly from A to zero (p) at the top of K its flight in a time kp. P , Va It then increases in velocity uniformly as it returns to the point of projection A.

(ii) The magnitude of the slope of the line AP = g or Ap\(^-\) = g, where g = acceleration of free fall due to gravity. The height attained when the ball is thrown up is equal to the area of the triangle AKP. The distance it falls from its maximum height is equal to the area of the triangle A\(^-\)PC which is equal to triangle AKP.

(c)(i) The second stone moves upwards and its acceleration g = 10m/s\(^2\). From equation v = u - gt

10 = 20 - 10t -10 = -10t

t = 1

The second stone has been in air for 1s before they met.

(ii) The first stone has been moving for (1 + 2)s = 3s

From equation v = u + gt

= 2 - (10 x 3) = 20 - 30 = -10m/s

The minus sign means the first stone is moving down and its velocity is 10m/s.

Correct Answer: C. He managed to get himself out of a difficult situation

Correct Answer: A. 96

Correct Answer: D. difficulties

Explanation

(a)The general arrangement of the viscera of man or rabbit shows that the diaphragm divides the trunk into two unequal parts namely, the upper chest cavity and the lower abdominal cavity. The chest cavity is enclosed or encircled by the ribs in which the lungs and the heart lie. The gullet runs down behind the mouth or buccal cavity through the whole length of the thoracic cavity, through the diaphragm. The liver lies below the diaphragm which over-laps a large portion of the stomach. The stomach leads to the small intestine which itself leads to the large intestine. The large intestine forms the caecum at one end and continues to form the rectum at the other end which finally terminates at the anus which lies at the posterior end of the trunk. Very close to the stomach are the pancreas and spleen. At the back of the abdominal cavity, we have a pair of kidneys. In male, the male part of the vasa diferensia are seen at the posterior region in close position with the bladder and ureter. In female, ovaries lie near the kidney, and the oviducts lead to the uterus or womb which is in the lower part of the abdominal cavity or behind the urinary bladder.

(b)(i)Hydra feeds mainly on small aquatic organisms.

-Food is captured by the help of nematocysts, borne on the tentacles.

-The food is then taken into the wide mouth by the tentacle.

-Here enzymes are secreted by the gland cells.

-digested extra cellularly and partially absorbed into endodermal cells.

-Here digestion is completed intra-cellularly.

(ii) Amoeba feeds on micro-organisms, e.g. diaton or organic particles. During feeding, it engulfs the food particles by forming cup shape. When the two ends of the pseudopodia touch, they fuse and enclose the food with little amount or drop of water and these form a food vacuole. The food is digested and absorbed here.

Correct Answer: C. his turnover will increase