Explanation

(a) Occupational mobility of labour is the ease with which labour/ a worker moves from one occupation to another.

(b)(i) Natural abilities required in certain occupation may prevent such labour from moving e.g. musicians, artists.

(ii) Cost of training may be high.

(iii) Trade union or professional association may inhibit such movements.

(iv) Labour may be too old to learn new skills.

(v) Differences in remuneration may prevent labour from moving from one occupation to another.

(vi) Discrimination on account of sex or race in some places may prevent mobility.

(vii) Inadequate information about wage rates and opportunities in other occupations.

(viii) Training may take a long period of time.

(c)(i) Education and training e.g. formal education and on-the-job training.

(ii) Good remuneration: Higher wages and salaries serve to motivate the work harder.

(iii) Good work environment: Good ventilation, good furnishing etc will make labour more efficient.

(iv) Availability of co-operant factors: Availability and quality of other factors such as land, equipment etc will make labour more efficient.

(v) Other conditions of service e.g. housing, transport, bonuses, scholarship for children, insurance coverage etc will make labour more efficient.

(vi) Degree of specialization: The more a worker specializes, the more efficient he or she becomes.

(vii) Good management style: A good management style encourages workers to be more efficient.

Correct Answer: D. Pihahiroth

Correct Answer: B. 10\(\sqrt{2}\)

Explanation

\(\sqrt{50} + \frac{10}}{\sqrt{2}} = \(\frac{\sqrt{50}}{1} + \sqrt{10}{\sqrt{2}}\)

= \(\frac{\sqrt{50 \times 2} + 10}{\sqrt{2}}\)

= \(\frac{\sqrt{100} + 10}{\sqrt{2}}\)

= \(\frac{10 + 10}{\sqrt{2} = \frac{20}{\sqrt{2}}\)

= \(\frac{20}{\sqrt{2}}\) \times \frac{\sqrt{2}}{\sqrt{2}}\)

= \(\frac{20\sqrt{2}}{2}\)

= 10\(\sqrt{2}\)

Correct Answer: A) 75%

Explanation

This question is asking about the probability of a man and his wife who both have the sickle cell trait having offspring that are either carriers or sicklers. Sickle cell trait is a genetic condition where a person has one normal hemoglobin gene and one abnormal hemoglobin gene. If a person inherits two abnormal hemoglobin genes, they will have sickle cell disease. Since both parents are heterozygous, it means they have one normal hemoglobin gene and one abnormal hemoglobin gene. When they have offspring, each parent will randomly pass on one of their genes to their child. Using a Punnett square, we can determine the probability of their offspring inheriting the sickle cell trait. In this case, the Punnett square would have the letters S and s representing the normal and abnormal hemoglobin genes, respectively. The possible combinations of genes in their offspring are SS, Ss, and ss. The probability of having an offspring with the sickle cell trait (Ss) is 50%. This is because there are two possible ways to get the Ss genotype: either the child receives the S gene from the father and the s gene from the mother, or the child receives the s gene from the father and the S gene from the mother. The probability of having an offspring with sickle cell disease (ss) is 25%. This is because the child must inherit the s gene from both parents. Therefore, the likely percentage of their offspring that will either be carriers or sicklers is 50% + 25% = 75%. This makes option A the correct answer. It's important to note that this question is based on Mendelian genetics, which is the study of how traits are inherited from parents to offspring. It is also important to know about genetic counseling and testing for sickle cell disease, especially for couples who are both carriers.

Correct Answer: C. They believed Jesus was claiming to be the Messiah

Correct Answer: B. avoid doubtful things

Correct Answer: B. Oba Olua

Correct Answer: D. 351

Correct Answer: C. elastic

Explanation

\(\stackrel\frown{AOB} = \stackrel\frown{BOC} = \stackrel\frown{COD} = \stackrel\frown{DOE} = 60°\)

In \(\Delta AOB\), Area of sector = \(\frac{60}{360} \times \frac{22}{7} \times 7^{2}\)

= \(25.67 cm^{2}\)

Area of triangle AOB = \(\frac{1}{2} \times \7 \times 7 \times \sin 60\)

= \(24.5 \times 0.866\)

= \(21.22 cm^{2}\)

Area of the 4 sectors = \(4 \times 25.67 = 102.68 cm^{2}\)

Area of the 4 triangles = \(4 \times 21.22 = 84.88 cm^{2}\)

Area of the shaded portion = \((102.68 - 84.88)cm^{2}\)

= \(17.80 cm^{2}\)

\(\approxeq 18 cm^{2}\)