Correct Answer: C) NADPH and ATP are synthesized using electron released from water

Explanation

The question is asking what happens during the light-dependent reaction in photosynthesis. The light-dependent reaction occurs in the thylakoid membrane of the chloroplast and it is the first stage of photosynthesis. It is called light-dependent reaction because light is the source of energy that drives the reaction. Option A, glucose is formed, is incorrect because glucose is not formed during the light-dependent reaction. Glucose is formed in the second stage, which is the light-independent reaction (also known as the Calvin Cycle). Option B, carbon IV oxide is fixed, is also incorrect because carbon dioxide is not fixed during the light-dependent reaction. Carbon dioxide is fixed during the light-independent reaction. Option C, NADPH and ATP are synthesized using electron released from water, is the correct option. During the light-dependent reaction, light energy is absorbed by chlorophyll and other pigments, which excite electrons that are then passed along a chain of electron carriers. The energy released during electron transport is used to pump protons across the thylakoid membrane, creating a concentration gradient that is used to create ATP. The electrons eventually end up on NADP+ and are used to make NADPH. Water is split to provide electrons to replace those that were lost from chlorophyll. Option D, water is split and the electrons produced are used for glucose synthesis, is incorrect because glucose is not synthesized during the light-dependent reaction. Glucose is synthesized during the light-independent reaction. Overall, the correct answer is option C because NADPH and ATP are synthesized using electrons released from water during the light-dependent reaction in photosynthesis.

Correct Answer: B. potential difference

Correct Answer: A. the arrangement of lines in verse form

Correct Answer: A. exits

Correct Answer: D. Ventifact

Correct Answer: B. synecdoche

Correct Answer: C. self-will

Correct Answer: C. Fulfill all righteousness

Explanation

(a) Solubility is the maximum amount of solute that would dissolve / be contained in 1 dm\(^3\) of solution at a given temperature.

(b)(i)

(ii) At 35° solubility = 0.50 to 0.55 moldm\(^{-3}\) range

(iii) Solubility @ 55°C = 0.95 to 0.98 moldm\(^{-3}\)

1 moldm\(^{-3}\) of salt Z = 0.97; 100 = 97g

100cm\(^{-3}\) will contain = \(\frac{97 \times 100}{100}\) = 9.7g

Solubility @ 35°C = 0.54moldm\(^{-3}\)

1 drn\(^{-3}\) contain = 0.54 x 100 = 54g

100cm\(^{-3}\) will contain 54 x100 = 5.4g

10 Mass of salt that would crystallize out = 9.7 - 5.4 = 4.3g

(c)(i) (I) Al\(_2\)O\(_{3(s)}\) + 6HCl\(_{(aq)}\) \(\to\) 2AlCl\(_{3(s)}\) + 3H\(_2\)O\(_{(l)}\)

(II) Al\(_2\)O\(_{3(g)}\) 2NaOH\(_{(aq)}\) + 3H\(_2\)O\(_{(l)}\) \(\to\) 2NaAl(OH)\(_4\)

(ii) Amphoteric

(iii) ZnO / PbO / SnO /Al\(_2\)O\(_3\)

d)(i) I [Al(H\(_2\)O)\(_6\)]\(^{3+}\) = x + (0) = +3

x = +3

Al = +3

(II) NaH = 1+ x = 0

x = —1

H = — 1

(ii)(I) Copper (II) tetraoxosulphate VI pentahydrate

(II) Calcium tripxocarbonate IV

(III) Potassium tetraoxomanganate VII.

Correct Answer: B. sp3 hybridized