Correct Answer: C. World Bank

Correct Answer: A. London constitutional conference of 1957

Correct Answer: A. He expected to see signs

Correct Answer: B) plumule

Explanation

This Biology question is asking about the name for the young shoot of a plant. The options provided are radical, plumule, bud, and branch. The correct answer is option B, plumule. A shoot is the part of the plant that grows upwards and carries the leaves, flowers, and fruits. The young shoot of a plant is referred to as a plumule. It is the embryonic shoot located above the cotyledon in the seed of a plant. The shoot system of a plant includes the stem, leaves, and flowers. The stem supports the plant, while the leaves are the primary sites for photosynthesis. The radical, on the other hand, is the embryonic root of a plant that grows downwards into the soil. The bud is a small, undeveloped shoot that has the potential to grow into a new branch or flower. A branch, on the other hand, is a secondary stem that grows out from the main stem of a plant. It is essential to understand the different parts of a plant, including the shoot system and root system, to have a better understanding of plant growth and development. Knowing the functions of each part of a plant can also help in identifying and treating plant diseases and pests. In summary, the young shoot of a plant is called a plumule, and it is an essential part of the shoot system. The radical is the embryonic root, while the bud is a small, undeveloped shoot that can grow into a new branch or flower. A branch, on the other hand, is a secondary stem that grows out from the main stem of a plant.

Correct Answer: B. King Uzziah died

Correct Answer: D. at conception

Correct Answer: A. in combination with haemoglobin

Correct Answer: C. 1.0

Explanation

To determine the number of faradays of electricity required, we need to follow these steps:

1. Write the half-reaction for the liberation of aluminium:

Aluminium is typically present as Al³⁺ ions. The reduction reaction at the cathode to liberate metallic aluminium is:

Al³⁺ + 3e⁻ → Al(s)

2. Determine the moles of aluminium to be liberated:

Given mass of aluminium = 9 g

Molar mass of aluminium (Al) = 27 g/mol

Moles of Al = Mass / Molar mass = 9 g / 27 g/mol = 1/3 mol

3. Relate moles of aluminium to moles of electrons:

From the half-reaction (Al³⁺ + 3e⁻ → Al), we see that 1 mole of Al requires 3 moles of electrons.

Therefore, for 1/3 mol of Al:

Moles of electrons = (1/3 mol Al) × (3 moles e⁻ / 1 mol Al)

Moles of electrons = 1 mol e⁻

4. Convert moles of electrons to Faradays:

One Faraday (1 F) is defined as the charge carried by one mole of electrons.

Since we need 1 mole of electrons, the quantity of electricity required is 1 Faraday.

Thus, 1 Faraday of electricity is required to liberate 9g of aluminium.

The final answer is 1.0.

Correct Answer: C) soaps

Correct Answer: A. Edo, the Yoruba and the Urhobo