Explanation

(a)i. 2KOH\(_{aq}\) + H\(_{2}\)SO\(_{4(aq)}\) \(\implies\) K\(_{2}\)SO\(_{4(aq)}\) + 2H\(_{2}\)O\(_{(l)}\)

ii. Amount of KOH used = \(\frac{24}{1000} \times \frac{0.150}{1}\) = 0.0036mol

Mole ratio of acid to base = 1:2

Amount of H\(_{2}\)SO\(_{4}\) used \(\frac{0.0036}{2}\) = 0.0018mol

\(\therefore\) Concentration of H\(_{2}\)SO\(_{4}\) = \(\frac{0.0018}{0.025}\) = 0.072mol dm\(^{-3}\)

(b)(i) Molar mass Mg(NO\(_{3}\))\(_{2}\) = 24 x 1 + 2 x [14 + (16 x 3)] 24 x 1 + 2 x [14 + 48] = 24 + 28 + 96 = 148 gmol\(^{-1}\)

Mass of N\(_{2}\) = 14 x 2- 28

\(\therefore\) %Nitrogen = \(\frac{28}{149} \times \frac{100}{1}\) = 18.9%

(c)i. Reaction with brominei n CCl\(_{4}\)/bromine water/H\(^{+}\) / K MnO\(_{4}\)/ H\(^{+}\) / K\(_{2}\)Cr\(_{2}\)O\(_{7}\)

- Reaction with aqueous NaHCO\(_{3}\)/ Na\(_{2}\)CO\(_{3}\). OR

- Reaction with alkanol + Conc. H\(+{2}\)SO\(_{4}\)

(ii) - Compound will decolourize bromine in CCl\(_{4}\)/ bromine water

- Change H\(^{+}\)/K\\(_{2}\)Cr\(_{2}\)O\(_{7}\) from orange to green.

- Change H\(^{+}\) /KMnO\(_{4}\) from purple to colourless.

- There will be effervescence/evolution of gas in reaction with NaCO\(_{3(aq)}\) / Production of sweet-smelling/fruity odour

(d) Add sufficient water to dissolve the pellets of NaOH. The solution is then added to the vegetable oil, stirred, and boiled. It is cooled to precipitate the soap/salt out the soap/salt. Filter off the soap takes off the soap crust.

(e) Define the Term Electronegativity: The tendency of an atom to pull to itself the shared pair of electrons in a covalent bond. The ability of an atom to attract shared electrons between It and another atom in a chemical bond

Correct Answer: D. Muhammad(SAW) should not be recognized as leader

Correct Answer: A. freezer

Explanation

(a) Draw an outline of the area to scale of 1:300,000.

Outline length 12.2cm ; Breadth 12.2cm

Note: The original length and breadth had been divided by 3.

(b)(i) Settlement of Pindiga and Yalo.

(ii) 1900ft contour line.

(iii) Full length of two minor roads.

Note: All these had been indicated in the drawn outline. 12.2 cm

(a)(b)

(c) Calculating the actual distance along the minor road from Futuk to the point where it leaves the area on the map. The distance in the map is 13.5 cm. The scale of the map is 1:100,000. Therefore the conversion of 13.5cm to the actual distance on the ground is

= 13.5 x100,000 km = 13.5km

100,000 1

(d) The influence of relief and drainage in the distribution of settlements shown on the map;

(i) The undulating plain to east of the area has many settlements.

(ii) Most settlements are near the river valleys.

(iii) Settlements avoid river valleys that are liable to flooding e.g. no settlement in the south-east due to flooding.

(iv) Settlements avoid the highland area in the west, north-west and south-west.

Correct Answer: B. barrier lakes

Correct Answer: C. \(\frac{\sqrt{2}}{2}\)

Explanation

Given tan x = 1

x = tan^-1(1)

x = 45^o

Now, \(\frac{1 - ( \frac{1}{\sqrt{2} )^2}}{\frac{1}{\sqrt{2}}}\)

= \(\frac{1 - \frac{1}{2}}{\frac{1}{2}}\)

= \(\frac{1}{2} + \frac{1}{\sqrt{2}}\)

= \(\frac{1}{2} \times \frac{1}{\sqrt{2}}\)

= \(\frac{\sqrt{2}}{2}\)

Correct Answer: A. records data while the latter interprets

Correct Answer: C. epigram

Correct Answer: B. Document specifying quantity, description, prices and total value of purchase .

Correct Answer: (D) RED