Correct Answer: A. ratio of the dependent to the working group

Correct Answer: D. 40N

Correct Answer: C. Herod sent Jesus back to Pilate

Correct Answer: A. I

Explanation

(a) \(y = (2x + 3)^{7} + \frac{x - 1}{2x - 1}\)

\(\frac{\mathrm d y}{\mathrm d x} = 7(2x + 3)^{6}. 2 + \frac{(2x - 1).1 - (x - 1).2}{(2x - 1)^{2}}\)

= \(14(2x + 3)^{6} + \frac{2x - 1 - 2x + 2}{(2x - 1)^{2}}\)

= \(14(2x + 3)^{6} + \frac{1}{(2x - 1)^{2}}\)

At x = -1, \(\frac{\mathrm d y}{\mathrm d x} = 14(-1)^{6} + \frac{1}{(2(-1) - 1)^{2}}\)

= \(\frac{\mathrm d y}{\mathrm d x} = 14 + \frac{1}{9} = 14\frac{1}{9}\)

(b) \(\int_{1} ^{2} \frac{x - 1}{(x + 2)^{4}} \mathrm d x\)

\( u = x + 2 \implies \mathrm d u = \mathrm d x\)

If x = 1, u = 1 + 2 = 3; x = 2, u = 2 + 2 = 4.

\(\int_{1} ^{2} \frac{x - 1}{(x + 2)^{4}} \mathrm d x = \int_{3} ^{4} \frac{u - 3}{u^{4}}\)

= \(\int_{3} ^{4} (\frac{u}{u^{4}} - \frac{3}{u^{4}}) \mathrm d u\)

= \(\int_{3} ^{4} (u^{-3} - 3u^{-4}) \mathrm d u\)

= \([\frac{u^{-2}}{-2} + u^{-3}]_{3} ^{4}\)

= \([\frac{1}{u^{3}} - \frac{1}{2u^{2}}]_{3} ^{4}\)

= \((\frac{1}{4^{3}} - \frac{1}{2(4^{2})}) - (\frac{1}{3^{3}} - \frac{1}{2(3^{2})})\)

= \(\frac{1}{64} - \frac{1}{32} - \frac{1}{27} + \frac{1}{18}\)

= \(\frac{5}{1728}\).

Correct Answer: C. normal profit

Correct Answer: A. contribution

Correct Answer: D. protected by it

Explanation

The correct answer is D. protected by it.

When a man is immune to an illness, his body has a defense system that protects him from getting sick from that particular illness, or from experiencing severe symptoms.

Correct Answer: A. Sahih

Correct Answer: D. 10 N

Explanation

Volume of water displaced = volume of cube

therefore, 0.1 x 0.1 x 0.1 = 0.001m³

mass of H₂O = 0.001 X 1000

= 1kg

upthrust = mg

= 1 x 10

=10N