Correct Answer: B. 0°

Explanation

Let the two forces be F1 and F2, and let the angle between them be θ.

The magnitude of the resultant force R is given by the formula:

R = sqrt(F1^2 + F2^2 + 2*F1*F2*cos(θ))

To maximize the resultant force R, we need to maximize the term under the square root. Since F1 and F2 are the magnitudes of the forces (and thus positive constants), F1^2, F2^2, and 2*F1*F2 are all constant positive terms.

Therefore, to maximize R, we need to maximize the value of cos(θ).

The maximum possible value of cos(θ) is 1.

This occurs when θ = 0°.

Let's check what happens at θ = 0°:

If θ = 0°, then cos(θ) = cos(0°) = 1.

R = sqrt(F1^2 + F2^2 + 2*F1*F2*(1))

R = sqrt((F1 + F2)^2)

R = F1 + F2

This represents the situation where the two forces act in the same direction, and their magnitudes add up, giving the largest possible resultant.

Let's quickly look at the other options:

• A. 45°: cos(45°) = √2/2 ≈ 0.707. This is less than 1.

• C. 90°: cos(90°) = 0. In this case, R = sqrt(F1^2 + F2^2). This is smaller than F1 + F2.

• D. 180°: cos(180°) = -1. In this case, R = sqrt(F1^2 + F2^2 - 2*F1*F2) = sqrt((F1 - F2)^2) = |F1 - F2|. This gives the minimum possible resultant force.

Therefore, the resultant of two forces is maximum if the angle between them is 0°.

The final answer is 0°

Correct Answer: B. mawdu

Correct Answer: B. true religion and social justice

Correct Answer: C. suitability for bulky and heavy cargo

Correct Answer: C. The HOd had asked if she wanted something to drink

Correct Answer: B. faith in God

Correct Answer: C. department store

Correct Answer: D. Ode

Correct Answer: B. nerves and hormones

Correct Answer: D. 10.8g

Explanation

Here's how to solve this problem using Faraday's laws of electrolysis:

1. Identify the half-reaction for silver deposition:

Silver ions are typically Ag⁺.

Ag⁺(aq) + e⁻ → Ag(s)

This reaction shows that 1 mole of electrons is required to deposit 1 mole of silver.

2. Relate moles of electrons to Faraday's constant:

One Faraday (1 F) is the charge carried by 1 mole of electrons.

From the half-reaction, 1 Faraday of electricity will deposit 1 mole of Ag.

3. Determine the mass of silver deposited by 1 Faraday:

The molar mass of Ag is given as 108 g/mol.

So, 1 F deposits 108 g of Ag.

4. Calculate the number of Faradays of electricity passed:

The total quantity of electricity (Q) is given as 98500 C.

The Faraday constant (F) is given as 985000 C/mol.

Number of Faradays = Total Charge (Q) / Faraday Constant (F)

Number of Faradays = 98500 C / 985000 C/mol = 0.1 Faradays

5. Calculate the mass of silver deposited:

Since 1 Faraday deposits 108 g of Ag, 0.1 Faradays will deposit:

Mass of Ag = 0.1 F * (108 g Ag / 1 F)

Mass of Ag = 10.8 g

The final answer is 10.8g