Correct Answer: A. Hairs

Correct Answer: D. Botswana

Correct Answer: B. 75.0 Nm⁻²

Correct Answer: B. funding

Explanation

The play is about conflict between tradition and modernity. Payment of the bride price is strictly attached to traditional marriage. Lakunle refuses to pay the traditional bride price for Sidi, losing her to Baroka.

Lakunle is a 'half-baked' educated young village teacher who places western values above traditional customs, including the payment of bride price. Sidi is the village beauty, she is simple, naive and has an overblown image of herself. She is the Jewel' of lujinle. She represents African traditional values. Baroka is the traditional ruler of lujinle and is 62 years. He upholds customs and employs wit and cunning to lure Sidi to join his many wives. He is the Lion of lujinle

Sadiku is the oldest wife of Baroka whom he inherited from the late chief, Okiki.She is simple- minded and used by Baroka to find other women to be his wives.

Lakunle's approach Sidi and criticizes traditional background, uneducated and uncultured.

Baroka sends Sadiku to Sidi with his proposal, Sadiku promises Sidi wealth, honour and prestige he sees Sidi as ignorant, if married to Baroka also praises Sidi's beauty and invites her to supper with Baroka at the palace and Baroka wins Sidi's love and later shares the secret of his impotence with Sadiku and Sadiku breaks the secret to Sidi, she goes to mock Baroka at his palace, Baroka lured Sidi to bed and she was shocked to discover the truth; Baroka is not impotent then Sidi snobs Lakunle for Baroka.

Correct Answer: A. an exemplary punishment

Correct Answer: C. qiran

Explanation

(a)

Description: The circuit is set up as shown above. The key (k) is closed. The rheostat (R) is adjusted so that lowest current is flowing. Ammeter and voltmeter readings (I and V) are recorded. Adjust rheostat to increase current. Ammeter and voltmeter readings are recorded for other positions of the rheostat. Values of (are plotted against values of I. Slope, which is the value of the resistance is determine.

Precautions;

i) Kcy should be removed when readings are not taken

ii) Connections should be tight

(iii) Parallax' error when reading ammeter and voltmeter should be avoided

(iv) Only low current should be used

v) Zero error of the meters should be avoided. Note: Any correct two) Resistance, R = P'/A where = length of wire, A = cross sectional area, p = resistivity )f wire. But slope, S of graph = R. Hence S = P'/A

Measure I with a metre rule. Measure diameter with a micrometer screw gauge and determine A. Substitute p = \(\frac{SA}{I}\)

c) Diagram

i) Total e.m.f. = 4V

Total resistance = 1 + 2 + \(\frac{3 \times 3}{ 2 \times 3}\)

= 3 + 1\(\frac{1}{2}\)

= \(\frac{1}{2} \Omega\)

E = IR\(_T\),

= E/R

:.Current, I = 4/9 x 2/1

= 8/9;

A = 0.9A

(ii) P.d = IR = 8/9 x 3/2 = 4/3 = 1.3V

(iii) Lost volts = Ir = \(\frac{8}{9}\) x 1 = \(\frac{8}{9} = 0.9V\)

Correct Answer: D) just below the root tip

Explanation

This question is asking about where the ridicule of a bean seedling grows most rapidly. The ridicule refers to the tiny root hairs that grow from the root of a plant. The options are A) of the root tip, B) below the top soil, C) just around the root tip, D) just below the root tip (which is the correct answer), and E) just above the root tip. The root tip is the part of the root that is actively growing and elongating. This is because new cells are constantly being produced at the root tip, which pushes the root through the soil. As the root grows, it is able to absorb more water and nutrients from the soil through its root hairs. In this case, the correct answer is D) just below the root tip. This is because the root hairs are most numerous and active in this region, as they are closest to the actively growing part of the root. As the root hairs absorb water and nutrients, the plant is able to grow more quickly and develop more leaves and stems above ground. Understanding the growth and function of root hairs is important in plant biology, as they are crucial for the survival and growth of plants. To learn more about this topic, please see the relevant chapters in your Biology textbooks.

Explanation

(a) \(\sqrt{50} - 3\sqrt{2}(2\sqrt{2} - 5) - 5\sqrt{32}\)

\(\sqrt{25 \times 2} - (3 \times 2)\sqrt{2 \times 2} + (3 \times 5)\sqrt{2} - 5\sqrt{16 \times 2}\)

= \(5\sqrt{2} - 6(2) + 15\sqrt{2} - 5(4\sqrt{2})\)

= \(5\sqrt{2} - 12 + 15\sqrt{2} - 20\sqrt{2}\)

= \((5 + 15 - 20)\sqrt{2} - 12\)

= -12.

(b) \(\frac{1}{2} \log_{10} (\frac{25}{4}) - 2 \log_{10} (\frac{4}{5}) + \log_{10} (\frac{320}{125})\)

= \(\log_{10} (\frac{25}{4})^{\frac{1}{2}} - \log_{10} (\frac{4}{5})^{2} + \log_{10} (\frac{320}{125})\)

= \(\log_{10} (\frac{5}{2}) - \log_{10} (\frac{16}{25}) + \log_{10} (\frac{320}{125})\)

= \(\log_{10} (\frac{\frac{5}{2} \times \frac{320}{125}}{\frac{16}{25}}\)

= \(\log_{10} (\frac{\frac{160}{25}}{\frac{16}{25}}\)

= \(\log_{10} 10 = 1\)