Correct Answer: A. the Transfiguration

Correct Answer: C. imprisoned

Correct Answer: A. Two blocks hit the ground simultaneously because they have the same acceleration

Explanation

An object falling without air resistance or friction is defined to be in free-fall. The acceleration of free-falling objects is therefore called the acceleration due to gravity. It is because the acceleration due to gravity is constant for all objects regardless of the mass, neglecting air resistance.

Explanation

(a) Area of the major sector = \(\frac{\theta}{360°} \times \pi r^{2}\)

= \(\frac{360 - 120}{360} \times \frac{22}{7} \times 7 \times 7\)

= \((\frac{2}{3} \times 154) cm^{2}\)

Volume = \(\text{Area of the major sector} \times \text{height (cross section)}\)

= \(\frac{2}{3} \times 154 \times 15 = 1540 cm^{3}\)

(b) Curved surface area = \(\frac{240}{360} \times 2\pi rh\)

= \(\frac{240}{360} \times 2 \times \frac{22}{7} \times 7 \times 15\)

= \(440 cm^{2}\)

Area of rectangular surface = \(2 \times l \times b\)

= \(2 \times 7 \times 15 = 210 cm^{2}\)

Area of top and bottom of cylinder (major sector)

= \(2 \times \frac{240}{360} \times \frac{22}{7} \times 7 \times 7\)

= \(205.33 cm^{2}\)

\(\therefore \text{Total surface area} = 440 + 205.33 + 210 = 855.33 cm^{2}\)

Correct Answer: A. Uqbah b. Nafi'

Correct Answer: A. \(\frac{1}{3}\)

Explanation

Differentiate distance twice to get the acceleration and then equate to get p.

\(s = 7 + pt^{3} + t^{2}\)

\(\frac{\mathrm d s}{\mathrm d t} = v(t) = 3pt^{2} + 2t\)

\(\frac{\mathrm d v}{\mathrm d t} = a(t) = 6pt + 2\)

\(a(3) = 6p(3) + 2 = 8 \implies 18p = 8 - 2 = 6\)

\(p = \frac{6}{18} = \frac{1}{3}\)

Correct Answer: (a) 499

Correct Answer: C. are found in the same habitat

Correct Answer: (a)onomatopoeia

Explanation

(a) \(\frac{m + n + s + p + q}{5} = 12 \)

\(\implies m + n + s + p + q = 12 \times 5 = 60\)

\(\frac{(m + 4) + (n - 3) + (s + 6) + (p - 2) + (q + 8)}{5} = \frac{m + n + s + p + q + 4 - 3 + 6 - 2 + 8}{5}\)

= \(\frac{60 + 13}{5} = \frac{73}{5}\)

= 14.6.

(b) In the community, there are 500 people.

The 75th percentile age = 65 years

Number of people in the 75th percentile = \(\frac{75 \times 500}{100} = 375\)

The 25th percentile = 15 years

Number of people in the 25th percentile = \(\frac{25 \times 500}{100} = 125\)

Number of people between 15 years and 65 years = 375 - 125 = 250 people.