Correct Answer: B) 0.7 moles

Explanation

To answer this question, we need to use the concept of molar mass and the relationship between mass, moles, and molar mass. The molar mass of a substance is the mass of one mole of that substance. A mole is a unit that represents a specific number of particles, such as atoms or molecules, in a sample of a substance.

The molar mass of X is given as 36g. To find the number of moles of X, we need to know the mass of X in the sample. Unfortunately, the question does not provide the mass of X in the sample. Without this information, we cannot determine the number of moles. However, the question states that the correct answer is 0.7 moles (Option B).

The relationship between mass, moles, and molar mass can be expressed as:

\(moles = \frac{mass}{molar\ mass}\)

Where moles represent the number of moles, mass represents the mass of the substance, and molar mass represents the molar mass of the substance.

Using this formula, you can calculate the number of moles if you are given the mass of the substance and its molar mass. However, as the mass of X is not provided in the question, the given answer (0.7 moles) might not be accurate.

Correct Answer: C. absence of the rule of law

Correct Answer: B. knowledge

Correct Answer: A. Bakelite

Correct Answer: B. Waraqah b. Nawfal

Correct Answer: A. men of faith

Correct Answer: D. Sales invoice

Correct Answer: C. the banishment of her lover

Explanation

28,Ireduwa Street,

Irepodun,

Ogun State.

29th March, 2019.

Dear Tunmise,

It's a pleasure writing to you once again. I hope you are doing great over there in Kaduna? I have missed you and I Know tnat the feeling is mutual. Anyway, as you already know that I hold the position of the Library Prefect in my school, I wish to share my experiences with you.

As you already know that I love reading, I was made the Library Prefect upon reaching SS3 class. As the Library Prefect, It is my duty to assist the Librarian when necessary. My duties include handling the borrowing and returning of books in the school library. I ensure that all the books in the library are accounted for. I make sure that every borrowed book is well documented and the names and classes of the borrowers are taken down. Doing this daily has helped me to be more accountable, I pay attention to details as a result of this role.

One of my duties is to maintain orderliness in the library. Whenever students are in the library seeking for books to read, ensure it is done in an orderly manner. Some students, especially the JSS One students have no idea how the books are arranged on each shelf, despite the indications on them. What I do in such situations is to lead them to the appropriate section, while advising them on the type of books to read.

When students are done reading, I ensure that the shelves are well-arranged and the library tidy always. I do this with the help of the school librarian, she advises from her wealth of experience. Doing this also made me more responsible as I learnt that responsibility comes from being given a role of leadership.

I wish i could keep on writing but I have to stop here. I hope you will share your own experiences with me as the Labour Prefect soon. My regards to your parents and siblings.

Yours sincerely,

Folarin.

Explanation

(a) \(3(3n - 1) + 5(2n + 1) = 135\)

\(9n - 3 + 10n + 5 = 135\)

\(19n + 2 = 135\)

\(19n = 135 - 2 = 133\)

\(n = \frac{133}{19} = 7\)

(b) Radius of a cylinder = 14 cm

side of a cube = 22 cm

\(\therefore \frac{22}{7} \times 14 \times 14 \times h = 22 \times 22 \times 22\)

\(44 \times 14 \times h = 22 \times 22 \times 22\)

\(h = \frac{22 \times 22 \times 22}{44 \times 14}\)

= \(\frac{121}{7} cm\)

TSA of a cylinder = \(2\pi r (r + h) = 2 \times \frac{22}{7} \times 14 (14 + \frac{121}{7})\)

= \(88(\frac{98 + 121}{7}) = \frac{88 \times 219}{7}\)

= \(\frac{19272}{7} cm^{2}\)

TSA of a cube = \(6s^{2}\)

= \(6 \times 22 \times 22\)

= \(2904 cm^{2}\)

Ratio = \(\frac{19272}{7} : 2904\)

= \(73 : 77\)