Correct Answer: C) resurrection

Explanation

In the book of Acts in the Bible, Paul was accused of preaching about foreign gods in Athens because he was teaching people about Jesus. The question is asking which specific aspect of Jesus' teachings Paul was accused of preaching, and the options are cross, law, resurrection, and second coming. The correct option is resurrection.

The resurrection is a central belief in Christianity, where Jesus is believed to have risen from the dead after being crucified. This event is seen as a victory over death and sin, and it demonstrates Jesus' power and authority. The resurrection is also seen as a sign of hope for Christians, who believe that they too will be resurrected after death and have eternal life with God.

In the context of the question, Paul was preaching about the resurrection of Jesus in Athens, which was seen as a foreign and unfamiliar concept to the people there. This led to accusations that he was promoting foreign gods. However, Paul was actually teaching about the same God that the Athenians worshipped, but with a new understanding of who God is and what He has done for humanity through Jesus.

So, in summary, the correct option in this question is resurrection, which refers to the central Christian belief that Jesus rose from the dead after being crucified.

Correct Answer: D. neither faith nor religion.

Correct Answer: B. i and iv

Correct Answer: C. nephridium

Correct Answer: A) Zn

Explanation

(a)(i)

(iv)

Determination of slope of graph

Slope = \(\frac{\Delta Q}{\Delta M}\)

= \(\frac{14.0 - 2.0) \times 10^3}{6.1 - 0.8}\)

= 2.26 x 10\(^3\)J/g

(v) Meaning of the value of the slope of graph

2.26 x 10\(^2\)J of heat energy is needed to evaporate 1g of water at constant temperature.

(b)(i) Explanation of saturated vapour pressure;

At any given temperature, some energetic molecules of a liquid in a given system escape from the liquid surface as vapour and at the same time some return to the liquid. Vapour pressure is built up above the liquid in the process. When the rate of escape equals the rate of return, the vapour is said to be saturated and the pressure it exerts is called saturated vapour pressure at that temperature.

(ii) Factor that affects saturated vapour pressure;

- Temperature

Correct Answer: B. credulous

Explanation

(a)

(b) \(\tan \theta = \frac{4.2}{6 + x} ; \tan \theta = \frac{1.2}{x}\)

\(\tan \theta = \tan \theta\)

\(\implies \frac{4.2}{6 + x} = \frac{1.2}{x}\)

\(4.2 x = 1.2(6 + x) \)

\(4.2 x = 7.2 + 1.2 x \implies 4.2x - 1.2x = 7.2\)

\(3x = 7.2 \implies x = 2.4 m\) (length of the shadow cast by the lamp)

(ii) \(\tan \theta = \frac{1.2}{2.4} = 0.5\)

\(\theta = \tan^{-1} (0.5) \)

= \(27°\) (angle of elevation)

Correct Answer: B. Cowrie

Explanation

\(\int_{1}^{3} (\frac{x - 1}{(x + 1)^{2}}) \mathrm {d} x\)

Let \(x + 1 = u, x - 1 = u - 2\)

When x = 3, u = 3 + 1 = 4

x = 1, u = 1 + 1 = 2

\(\therefore \int_{1}^{3} (\frac{x - 1}{(x + 1)^{2}}) \mathrm {d} x \equiv \int_{2}^{4} (\frac{u - 2}{u^{2}}) \mathrm {d} u\)

= \(\int_{2}^{4} (\frac{u}{u^{2}} - \frac{2}{u^{2}}) \mathrm {d} u\)

= \(\int_{2}^{4} (\frac{1}{u} - 2u^{-2}) \mathrm {d} u\)

= \([\ln u - \frac{2u^{-1}}{-1}]|_{2}^{4}\)

= \([\ln u + 2u^{-1}]|_{2}^{4}\)

= \([\ln u + \frac{2}{u}]|_{2}^{4}\)

= \((\ln 4 + \frac{2}{4}) - (\ln 2 + \frac{2}{2})\)

= \(\ln 4 - \ln 2 - \frac{1}{2}\)

= \(\ln (\frac{4}{2}) - \frac{1}{2}\)

= \(\ln 2 - \frac{1}{2}\).