Correct Answer: C) 3.0

Correct Answer: B. secretions from the vulva

Correct Answer: D. onomatopoeia

Correct Answer: C. marketing boards

Correct Answer: B. unyielding about / retailatory

Correct Answer: A) 34.0

Explanation

The question is asking about an element X that reacts with a volatile hydride XH\(_3\) with a density of 17.2. The question is asking for the relative atomic mass of X. To understand this question, we need to know about relative atomic mass, which is the average mass of an atom of an element, taking into account all its isotopes and their relative abundance. Isotopes are atoms of the same element that have different numbers of neutrons in their nucleus, and therefore have different atomic masses. The fact that the hydride XH\(_3\) is volatile means that it easily evaporates at room temperature. The density of the hydride is given as 17.2, which means that it is heavier than air. When an element reacts with a hydride, it forms a compound that contains the element and hydrogen. In this case, the hydride is XH\(_3\), which means that it contains one atom of X and three atoms of hydrogen. To find the relative atomic mass of X, we need to use the density of the hydride. The density is related to the molar mass of the compound, which is the mass of one mole of the compound. One mole of XH\(_3\) contains one mole of X atoms and three moles of hydrogen atoms. We can use the formula density = (molar mass) / (molar volume) to find the molar mass of XH\(_3\). The molar volume of a gas at standard temperature and pressure (STP) is 22.4 L/mol. Since the hydride is volatile, we can assume that it is a gas at STP. Therefore, the molar mass of XH\(_3\) is: molar mass = density x molar volume = 17.2 x 22.4 = 385.28 g/mol. Since one mole of XH\(_3\) contains one mole of X atoms, the molar mass of X is equal to the molar mass of XH\(_3\) minus three times the molar mass of hydrogen: molar mass of X = molar mass of XH\(_3\) - 3 x molar mass of hydrogen = 385.28 - 3 x 1.008 = 382.256 g/mol. This is not one of the answer options given in the question. However, we can divide this value by the mass of one mole of carbon-12 (12 g/mol) to get the relative atomic mass of X: relative atomic mass of X = molar mass of X / 12 = 382.256 / 12 = 31.8547. This value is closest to option A, which is 34.0. Therefore, option A is the correct answer. In summary, the question is asking for the relative atomic mass of an element X that reacts with a volatile hydride XH\(_3\) with a density of 17.2. We can find the relative atomic mass by using the formula density = (molar mass) / (molar volume) and subtracting the molar mass of three hydrogen atoms from the molar mass of XH\(_3\). We can then divide this value by the mass of one mole of carbon-12 to get the relative atomic mass of X. Option A, which is 34.0, is the correct answer.

Correct Answer: C. 7

Explanation

When finding the median, you are looking for the middle number. Always arrange the numbers in ascending order. Since, the numbers are inceasing, count the numbers in the set. There are five. Then divide five by two. We do this because we will split the number set in half. Because five doesn't divide evenly into two, this means we can easily determine the median. Since five divided by two is 2.5, we are going to eliminate two numbers from leftmost in number set toward the right direction and two numbers from rightmost in number set toward the left direction. The only number left is 7 and therefore is the right answer.

Correct Answer: D. acting as acceptance houses

Correct Answer: A. 1:1

Explanation

Range = \(\frac{U^2sin2{\theta}}{g}\)

\(\frac{R_x}{R_y}\) = \(\frac{U^2_xsin60}{U^2_ysin120}\)

sin60^o = sin120^o

\(\frac{R_x}{R_y}\) = \(\frac{1}{1}\)

hence, = 1:1

Explanation

(a)(i) Lines of longitude are imaginary lines running from north to south on the earth's surface while lines of latitude are imaginary lines on the earth's surface running from east to west.

(ii) All lines of latitude are parallel while lines of longitude converge at the poles

(iii) All opposite lines of longitude form great circles while the Equator is the only line of latitude that forms a great circle

(iv) Lines of latitudes are used for calculating distance while lines of longitude are used for calculating local time of places

(v) Lines of latitude decrease in length from the

equator towards the poles while all lines of longitude are of equal length

(vi) Line of latitude increase in value from the equator towards the poles while lines of longitude increase in value eastwards and westwards of the Greenwich meridian

(vii) The significant lines of latitude are 0°, 23112°N, 231/2°S, 661/2°N, 661/2°S and 90°N and S, while those of longitude are 0° and 180° East and West.

(b) Solution:The average distance of 1° of latitude = 111km. Difference in latitude between Tema and London,

i.e 52° - 6° = 46°, Actual distance = 111 x 46° = 5,106km