Correct Answer: C. tropical maritime and the tropical continental

Correct Answer: B. John Beecroft

Correct Answer: B. -198 kJ mol-

Explanation

a.(i). Citizenship can be acquired by birth i.e, born by parents who are citizens of the country/state.

(ii). Citizenship can be acquired by naturalization; a citizen of another country can apply for citizenship of another country , where he/she resides.

(iii). Citizenship by registration i.e, through marriage.

(iv). Citizenship by descent or when grandparents claimed to have migrated from somewhere.

(v). Adoption through legal process.

(vi). Honorary / conferment by the state.

(vii). Conquest through wars and subjugations.

(viii). Foundling; this citizenship involves rescueing of children on the streets.

b.(i) The alien must have good character or of good reputation.

(ii). The alien must have married a citizen for not less than a period of 5 years.

(iii). he/she must have lived in the country for a very long period of time which may range from 15-20 years.

(iv). The alien must have renounced his/her former nationality.

(v). The applicant for citizenship must take the oath of allegiance

(vi). He/she must be of a matured age i.e. eighteen (18) years.

(vii). The alien must be capable of contributing meaningfully to the advancement and progress of the country.

(viii). He/she must be acceptable to the locality where he/she is residing.

Explanation

\(\lambda = \frac{h}{p} = \frac{h}{mv}\)

V = \(\frac{h}{m_2}\)

Electron kitenic energy = \(\frac{1}{2} MV^2 = \frac{h^2}{2m \lambda^2}\)

= \(\frac{(6.6 \times 10^{-34})^2}{2 \times 9.0 \times 10^{-37} \times 1.0 \times 10^{-20}}\) = 2.39 x 10\(^{-17}\)J

Correct Answer: C. \(\frac{1}{36}\)

Correct Answer: B) Television

Explanation

Radio, on the other hand, only relies on sound to convey messages. Print media, such as newspapers and magazines, primarily uses text and images without sound. Posters are static visuals without any accompanying sound or motion.

Therefore, in terms of combining sight and sound, television is the advertising medium that best fits this description.

Correct Answer: A. offering for the saints

Correct Answer: C. pretended

Explanation

\(\tan 2A = \frac{2 \tan A}{1 - \tan^{2} A}\)

\(\tan 30 = \tan 2(15°)\)

\(\frac{\sqrt{3}}{3} = \frac{2 \tan 15}{1 - \tan^{2} 15°}\)

\(\frac{\sqrt{3}}{6} = \frac{\tan 15}{1 - tan^{2} 15°}\)

Let \(\tan 15° = x\)

\(\frac{\sqrt{3}}{6} = \frac{x}{1 - x^{2}}\)

\(\sqrt{3} (1 - x^{2}) = 6x \implies \sqrt{3} - \sqrt{3} x^{2} = 6x \)

\(\sqrt{3} x^{2} + 6x - \sqrt{3} = 0\)

Divide through by the coefficient of x\(^{2}\).

\(x^{2} + \frac{6}{\sqrt{3}} x - 1 = 0\)

\(\implies x^{2} + 2\sqrt{3} x - 1 = 0\)

\(x = \frac{-(2\sqrt{3}) \pm \sqrt{(2\sqrt{3})^{2} - 4(1)(-1)}}{2(1)}\)

\(x = \frac{-2\sqrt{3} \pm \sqrt{16}}{2} = \frac{-2\sqrt{3} \pm 4}{2}\)

\(x = -\sqrt{3} + 2 ; x = -\sqrt{3} - 2\)

Since 15° is in the first quadrant, \(\tan 15° > 0\)

\(\therefore \tan 15° = -\sqrt{3} + 2 \equiv 2 - \sqrt{3}\).