Correct Answer: A) Former is limited to fifty shareholders but not the latter

Explanation

The question is asking how private and public limited liability companies are different. The options provide different statements, and we need to choose the correct one.

The correct option is Option A, which says that private limited liability companies are limited to fifty shareholders, while public limited liability companies are not.

A limited liability company is a type of business structure where the owners (shareholders) are not personally liable for the company's debts. This means that if the company goes bankrupt or is sued, the shareholders' personal assets are protected.

Private limited liability companies are often smaller and have fewer shareholders, while public limited liability companies are larger and have more shareholders. Public limited liability companies can also raise capital by selling shares to the public, while private limited liability companies cannot.

It is important to note that both private and public limited liability companies are legal entities, which means that they can enter into contracts, own property, and sue or be sued in court.

To summarize, private and public limited liability companies differ in the number of shareholders they can have, with private limited liability companies being limited to fifty shareholders. Both types of companies are legal entities, which means they have legal rights and responsibilities.

Correct Answer: D. surprised

Correct Answer: C. 30 J

Explanation

Using, v² = u² - 2gx

(20)² = u²1/2 x 10 x 10

u² = 600(m/s)²

initial K.E = - mu²

= \(\frac{1}{2}\) x 600

= 30 J

Correct Answer: A. metaphor

Correct Answer: D. Muhammad b. Abdullah

Correct Answer: A) 1 - propanol and 2 - propanol

Explanation

(a)(i) \(A(1 + r) + A(1 + r)^{2} + ... + A(1 + r)^{n}\)

\(S_{n} = \frac{a(r^{n} - 1)}{r - 1}\) (sum of terms in a G.P).

\(a = A(1 + r) ; r = (1 + r)\)

\(S_{n} = \(\frac{(A(1 + r))[(1 + r)^{n} - 1]}{(1 + r) - 1}\)

= \(\frac{(A(1 + r))[(1 + r)^{n} - 1]}{r}\)

(ii) Sum of the 6th to 10th term = \(S_{10} - S_{5}\)

\(a = 40(1 + 0.08) = 43.2 ; r = 0.08\)

\(S_{10} = \frac{43.2[(1 + 0.08)^{10} - 1]}{0.08} = 540[(1.08)^{10} - 1]\)

\(S_{5} = \frac{43.2[(1.08)^{5} - 1]}{0.08} = 540[(1.08)^{5} - 1]\)

\(S_{10} - S_{5} = 540[(1.08)^{10} - (1.08)^{5}]\)

= 371.8

(b) \(y = \frac{1}{x} = x^{-1}\)

\(\frac{\mathrm d y}{\mathrm d x} = -x^{-2}\)

When \(x = 2; y = \frac{1}{2}\), a point on the curve.

Gradient of tangent = \(-2^{-2} = -\frac{1}{4}\)

Equation : \(\frac{y - \frac{1}{2}}{x - 2} = -\frac{1}{4}\)

\(4y - 2 = 2 - x \implies x + 4y - 4 = 0\)

Correct Answer: B. panicum maximum

Correct Answer: A. bought at given price at a time

Correct Answer: D. banking