Explanation

Phil. 2:1-11: (a)

(i) Paul taught that humility implies that Christians should be of one mind.

(ii) and that they should love one another.

(iii) He believes nothing should be done from selfishness or conceit.

(iv) Christians should in humility, count others better than themselves.

(v) The interests of others should be projected above personal interests.

(vi) Christ's example of humility stands out: though in the form of God, he did not exalt himself.

(vii) But emptied himself, taking the form of a servant, born in the likeness of men.

(viii) In his human form, Jesus became obedient even to the point of death - a shameful death on the cross.

(ix) For this obvious demonstration of humility God has highly exalted Jesus.

(x) He bestowed on him the name which is above every name.

(xi) That at the name of Jesus, every knee should bow.

(xii) And tongue confess that Jesus Christ is Lord.

(b) Ways the teaching is relevant to Christians

(I) Humility makes living/societal interaction easier.

(ii) It leads to selflessness.

(iii) It attracts respect.

(iv) It promotes tolerance and consensus.

(v) It brings exaltation.

(vi) It makes one submit to those in authority.

Correct Answer: B. Tend to gain electrons in chemical reactions

Explanation

Tend to gain electrons in chemical reactions. Non-metals typically have a high electronegativity and tend to gain electrons to achieve a stable electron configuration. This results in the formation of negatively charged ions (anions) during chemical reactions.

Correct Answer: D. AB

Explanation

(a) \(\frac{2x^{2} - 5x + 1}{x^{3} - 4x^{2} + 3x}\)

\(x^{3} - 4x^{2} + 3x = x(x^{2} - 4x + 3)\)

\(x^{2} - 4x + 3 = (x - 1)(x - 3)\)

\(\therefore x^{3} - 4x^{2} + 3x = x(x - 1)(x - 3)\)

\(\implies \frac{2x^{2} - 5x + 1}{x^{3} - 4x^{2} + 3x} = \frac{A}{x} + \frac{B}{x - 1} + \frac{C}{x - 3}\)

\(\implies \frac{2x^{2} - 5x + 1}{x^{3} - 4x^{2} + 3x} = \frac{A(x - 1)(x - 3) + B(x)(x - 3) + C(x)(x - 1)}{x(x - 1)(x - 3)}\)

Equating, we have

\(2x^{2} - 5x + 1 = A(x - 1)(x - 3) + B(x)(x - 3) + C(x)(x - 1) \)

Let x = 1, we have

\(2 - 5 + 1 = -2B \implies B = 1\)

Let x = 3, we have

\(18 - 15 + 1 = 6C \implies C = \frac{4}{6} = \frac{2}{3}\)

Let x = 0, we have

\(0 - 0 + 1 = 3A \implies A = \frac{1}{3}\)

\(\therefore \frac{2x^{2} - 5x + 1}{x^{3} - 4x^{2} + 3x} = \frac{1}{3x} + \frac{1}{x - 1} + \frac{2}{3(x - 3)}\)

(b) \(\begin{vmatrix} x - 3 & -4 & 3 \\ 5 & 2 & 2 \\ 2 & -4 & 6 - x \end{vmatrix} = -24\)

\(\implies (x - 3)(12 - 2x + 8) - (-4)(30 - 5x - 4) + 3(-20 - 4) = -24\)

\((x - 3)(20 - 2x) + 4(26 - 5x) - 72 + 24 = 0\)

\(20x - 2x^{2} - 60 + 6x + 104 - 20x - 48 = 0\)

\(-2x^{2} + 6x - 4 = 0\)

\(2x^{2} - 6x + 4 = 0\)

\(2x^{2} - 4x - 2x + 4 = 0 \implies 2x(x - 2) - 2(x - 2) = 0\)

\((2x - 2)(x - 2) = 0 \implies \text{x = 1 or 2}\).

Correct Answer: B. their highest occupied enegy level is full

Correct Answer: C. girl is a minor

Correct Answer: C. 250^oC

Correct Answer: D. Wholesalers and retailers

Correct Answer: A. creation

Correct Answer: B. make up