Explanation

i. Responsible and accountable to the British parliament.

ii. Advised the governors on the affairs of the colonies e.g. during crisis.

iii. Recommended people to the crown to be appointed as governors for the colonies.

iv. Supervised the colonial administration by giving directives to the Governors based on the British policies.

v. Received petitions and grievances from the colonies on behalf of the British parliament.

vi. Submitted annual reports to the British on the colonies to the crown through the parliament.

vii. Approved the drafting of a new constitution for the colonies.

viii. Controlled the finances of the colonies through approval of budgets and auditing of accounts.

x. Set up Commissions of enquiry to investigate issues in the colonies.

xi. He could disallow any law which was not consistent with British colonial policies.

xii. He could override the Governors veto and power of certification.

xiii. He approved major projects to be undertaken in the colonies.

Correct Answer: B. an excellent spirit was in him

Explanation

Total ratio = 3 + 5 + 8 = 26

Ali's share is \(\frac{3}{16}\) x N420,000

= N78,000

Yusuf's share is \(\frac{8}{16}\) x N420,000

= N210,000

Sum of Ali's share + Yusuf's share

= N78,750 + N210,000

= N288,750

(b) 2(\(\frac{1}{8}\))\(^2\) = 32\(^{x - 1}\)

2\(^{1}\) x 2\(^{3x}\) = 2\(^{5x - 5}\)

2\(^{1 - 3x}\) = 2\(^{5x - 5}\)

1 - 3x = 5x - 5

-3x - 5x = -5 -1

-8x = -6

x = \(\frac{-6}{-8}\)

= \(\frac{3}{4}\)

Correct Answer: D. tomato and yam

Correct Answer: B. 4π

Correct Answer: D. doing the will of God

Correct Answer: A. promote and protect the security of the nation

Correct Answer: D) can be used by any type of business

Correct Answer: B. the forest consists of scattered trees only

Explanation

(a) \(T_{n} = a + (n - 1)d\) (terms of an AP)

Given a = -8;

\(T_{7} = a + 6d = -8 + 6d\)

\(T_{9} = a + 8d = -8 + 8d\)

\(\frac{-8 + 6d}{-8 + 8d} = \frac{5}{8}\)

\(5(-8 + 8d) = 8(-8 + 6d)\)

\(-40 + 40d = -64 + 48d\)

\(-40 + 64 = 48d - 40d \times 24 = 8d\)

\( d = 3\)

(b) Given r = 2 cm, m = 11.2g

(i) \(V = \frac{4}{3} \pi r^{3}\)

= \(\frac{4}{3} \times \frac{22}{7} \times 2^{3}\)

= \(\frac{704}{21}\)

= \(33.52 cm^{3} = 33.52 \times 10^{-6} m^{3}\)

= \(3.352 \times 10^{-5} m^{3}\)

(ii) \(Density = \frac{mass}{volume}\)

= \(\frac{11.2}{33.52}\)

= \(0.334 g/cm^{3}\)

(iii) \(V = \frac{4}{3} \pi r^{3}\)

= \(\frac{4}{3} \times \frac{22}{7} \times 3^{3}\)

= \(\frac{2376}{21}\)

= \(113.14 cm^{3}\)

\(mass = density \times volume\)

\(0.334 \times 113.14 = 37.789g\)